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NEW QUESTION: 1
On Cisco routers, there are two mutually exclusive types of RSA key pairs: special-usage keys and general-purpose keys. When you generate RSA key pairs, you are prompted to select either special-usage keys or general-purpose keys. Which set of statements is true?
A. special-usage key pair is default in Cisco IOS
B. If you generate special-usage keys, two pairs of RSA keys are generated. One pair is used with any IKE policy that specifies RSA signatures as the authentication method. The other pair is used with any IKE policy that specifies RSA encrypted keys as the authentication method.
C. If you generate a named key pair, only one pair of RSA keys is generated. This pair is used with IKE policies that specify either RSA signatures or RSA encrypted keys. Therefore, a general-purpose key pair might be used more frequently than a special-usage key pair.
D. If you generate general-purpose keys, you must also specify the usage-key keyword or the general-key keyword. Named key pairs allow you to have multiple RSA key pairs, enabling the Cisco IOS Software to maintain a different key pair for each identity certificate.
Answer: B
Explanation:
General-keys: Specifies that a general-purpose key pair will be generated, which is the default. Usage-keys: Specifies that two RSA special-usage key pairs, one encryption pair and one signature pair, will be generated. If you generate special-usage keys, two pairs of RSA keys are generated. One pair is used with any IKE policy that specifies RSA signatures as the authentication method. The other pair is used with any IKE policy that specifies RSA encrypted keys as the authentication method.
NEW QUESTION: 2
ネットワークにはActive Directoryフォレストが含まれています。 フォレストにはcontoso.comという名前のドメインが含まれています。 ドメインには3つのドメインコントローラーが含まれています。
lon-dc1という名前のドメインコントローラーが失敗します。 lon-dc1は修復できません。
他のドメインコントローラがlon-dc1に複製しようとしないようにする必要があります。
ソリューション：Active Directoryユーザーとコンピュータから、lon-dc1のコンピュータアカウントを削除します。
これは目標を満たしていますか？
A. はい
B. いいえ
Answer: A
Explanation:
To remove the failed server object from the domain controllers container, access Active Directory Users and Computers, expand the domain controllers container, and delete the computer object associated with the failed domain controller References:
https://www.petri.com/delete_failed_dcs_from_ad
NEW QUESTION: 3
Windows Server 2016を実行するServer1という名前のサーバーがあります。Server1には、Windowsアプリケーションプロキシの役割サービスがインストールされています。
新しいアプリケーションの発行ウィザードを使用してMicrosoft Exchange ActiveSyncサービスを発行する必要があります。
ActiveSyncサービスは事前認証を使用する必要があります。
Server1をどのように構成しますか？ 回答するには、回答領域で適切なオプションを選択します。
Answer:
Explanation:
NEW QUESTION: 4
Which of the following will help prevent smurf attacks?
A. Allowing necessary UDP packets in and out of the network
B. Disabling unused services on the gateway firewall
C. Disabling directed broadcast on border routers
D. Flash the BIOS with the latest firmware
Answer: C
Explanation:
Explanation/Reference:
Explanation:
A smurf attack involves sending PING requests to a broadcast address. Therefore, we can prevent smurf attacks by blocking broadcast packets on our external routers.
A smurf attack is a type of network security breach in which a network connected to the Internet is swamped with replies to ICMP echo (PING) requests. A smurf attacker sends PING requests to an Internet broadcast address. These are special addresses that broadcast all received messages to the hosts connected to the subnet. Each broadcast address can support up to 255 hosts, so a single PING request can be multiplied 255 times. The return address of the request itself is spoofed to be the address of the attacker's victim. All the hosts receiving the PING request reply to this victim's address instead of the real sender's address. A single attacker sending hundreds or thousands of these PING messages per second can fill the victim's T-1 (or even T-3) line with ping replies, bring the entire Internet service to its knees.
Smurfing falls under the general category of Denial of Service attacks -- security attacks that don't try to steal information, but instead attempt to disable a computer or network.