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NEW QUESTION: 1
A customer has Microsoft Windows, Oracle, and Power servers with internal disk. They are porting several applications from other platforms to these servers and need 5 TB of shared disk.
Which of the following is the most cost effective, highly available, shared storage solution for this customer?
A. DS8700 Storage Server
B. N5200
C. DS3500 Storage Server
D. DS5300 Storage Server
Answer: D
NEW QUESTION: 2
新しいキー数値が導入されました。これらをIBP Excelアドインで使用して、転送、購入、または生産される最大供給量を設定できます。制約によりこの上限に到達することが不可能である場合、可能な限り転送、購入、または生産されます。この値を0に設定すると、これが最大供給量になります。以下は、SAP7サンプル計画領域の新しいキー数値です。
注：この質問には2つの正解があります
A. 調整された流通領収書（レーン）（ADJUSTEDDISTRRECEIPTLXNE）：これは、タイププラントの出荷元の場所から出荷先の場所に配布される資材の入庫数量の調整値を含む格納されたキー数値です。タイプ植物。対応するビジネス上の意味にマップされている場合、それを使用して、在庫転送および購入の数を調整できます。
B. Microsoft Excelプランニングビューチャートのマット。
C. 調整済み生産レシート（PDS）（ADJUSTEDPRODRECEIPTPDS）：これは、特定の生産データソースの生産数量の調整値を含む格納されたキー数値です。
Answer: A,B
NEW QUESTION: 3
The developer wants to write a criteria query that will return the number of orders made by customer of each county.
Assume that customer is an entity with a unidirectional one-to-many relationship to the Order entity and that Address is an embeddable class, with an attribute country of type String.
Which one of the queries below correctly achieves this?
A. CriteriaBuilder cb = ...
CriteriaQuery cq = cb.createQueryO;
Root<Customer> c = cq.from(Customer.class);
Root<Customer> c = cq . from (Customer . class ) ,-
Join<Customer, Order> o = c.join(Customer_.orders);
Join<Address, String> country= c.join(Customer,.address) .join(Address
cq.multiselect(cq.count(o), country );
cq.groupBy(c.get(Customer.address)- get (Address_ . country) ) ;
B. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Customer> c = cq.from(Customer.class); cq.select (cb.count(c.join
(customer_. Orders)) , c.get(customers(0), c.get(customer_.address) . get (Address_'country));
(c.get(Customer_.address). get(address_.country));
C. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.multiselect(cb.count(0), c,get(customer_.address.get(address_.country)
cq.groupBy (c.get(customer_.address) .get(address_.country))
D. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Custower> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.select(cb.count(o));
cq.groupBy(c.qet(Customer__.address) - get(Address_.country)) ;
Answer: C
Explanation:
Reference:http://www.jarvana.com/jarvana/view/org/apache/openjpa/openjpa-persistencejdbc/2.0.0/openjpa-persistence-jdbc-2.0.0-testsources.jar!/org/apache/openjpa/persistence/criteria/TestTypesafeCriteria.java?format=ok