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NEW QUESTION: 1
A. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
C. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
D. CustNo
E. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo
I. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo
J. CustNoWHERE D.CustNo IS NULL
Answer: I
Explanation:
Explanation
The RIGHT JOIN keyword returns all records from the right table (table2), and the matched records from the left table (table1). The result is NULL from the left side, when there is no match.
References: https://www.w3schools.com/sql/sql_join_right.asp
NEW QUESTION: 2
A collaboration engineer has set up SAF on a Cisco IOS router to advertise and accept SAF information during a
maintenance window. Which two commands enable this functionality? (Choose two.)
A. advertise callcontrol 1
B. register callcontrol wildcarded
C. publish callcontrol 1
D. distribute callcontrol 1
E. subscribe callcontrol wildcarded
F. enroll callcontrol wildcarded
Answer: C,E
NEW QUESTION: 3
In a network with dozens of switches, how many root bridges would you have?
A. 0
B. 1
C. 2
D. 3
Answer: D