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NEW QUESTION: 1
FTP and TFTP can be used to update the system file on Huawei routers. Which of the following statements are correct? (Choose three)
A. Huawei router can be configured as TFTP Server
B. Huawei router can be configured as FTP Server
C. Huawei router can be configured as TFTP Client
D. Huawei router can be configured as FTP Client
Answer: B,C,D
NEW QUESTION: 2
You are the project manager of the GHQ Project. You have to prioritize activities for the effective management of project. For this, you have created a network diagram to schedule a set of project activities as shown in the figure:
Based on this figure, what is the critical path of this project?
A. ABEHJ
B. ACFIJ
C. ADGJ
D. ACFGJ
Answer: D
Explanation:
Explanation/Reference:
Explanation:
The activity nodes of path ACFGJ equals 26 days and is the longest path to completion - it is the critical path.
ACFGJ= A(4)+C(8)+F(4)+G(6)+J(4)=26
What is a critical path?
A critical path is the sequence of project activities, which add up to the longest overall duration. This determines the shortest time possible to complete the project. Any delay of an activity on the critical path directly impacts the planned project completion date (i.e. there is no float on the critical path). A project can have several, parallel, near critical paths. An additional parallel path through the network with the total durations shorter than the critical path is called a sub-critical or non-critical path. These results allow managers to prioritize activities for the effective management of project completion, and to shorten the planned critical path of a project by pruning critical path activities, by "fast tracking" (i.e., performing more activities in parallel), and/or by "crashing the critical path" (i.e., shortening the durations of critical path activities by adding resources).
Incorrect Answers:
A: ABEHJ takes only 22 days to complete; it is not the critical path. ABEHJ=A(4)+B(5)+E(2)+H(7)+J(4)=22 B: ACFIJ takes only 23 days to complete; it is not the critical path. ACFIJ=A(4)+C(8)+F(4)+I(3)+J(4)=23 C: ADGJ takes only 15 days to complete; it is not the critical path. ADGJ=A(4)+D(1)+G(6)+J(4)=15
NEW QUESTION: 3
Given: interface Pet { }
class Dog implements Pet { }
public class Beagle extends Dog{ }
Which three are valid?
A. Dog d = new Beagle();
B. Beagle c = new Dog();
C. Pet e = new Beagle();
D. Dog f = new Pet();
E. Pet a = new Dog();
F. Pet b = new Pet();
Answer: A,C,E
Explanation:
Incorrect:
Not B, not C: Pet is abstact, cannot be instantiated.
Not F: incompatible type. Required Beagle, found Dog.
NEW QUESTION: 4
Your network contains an Active Directory domain named contoso.com. All servers run Windows Server 2012 R2. The network contains a System Center 2012 R2 Data Protection Manager (DPM) deployment.
The domain contains six servers. The servers are configured as shown in the following table.
You install System Center 2012 R2 Virtual Machine Manager (VMM) on the nodes in Cluster2.
You configure VMM to use a database in Cluster1. Server5 is the first node in the cluster.
You need to back up the VMM encryption key.
What should you back up?
A. a system state backup of Server2
B. a system state backup of Server5
C. a full system backup of Server3
D. a full system backup of Server6
Answer: A
Explanation:
Encryption keys in Active Directory Domain Services: If distributed key management (DKM) is configured, then you are storing VMM-related encryption keys in Active Directory Domain Services (AD DS). To back up these keys, back up
Active Directory on a regular basis.
Reference:
Back Up and Restore Virtual Machine Manager
https://technet.microsoft.com/en-us/library/dn768227.aspx#BKMK_b_misc