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NEW QUESTION: 1
A router has two paths to reach another network in a different autonomous system. Neither route was generated by the local router and both routes have the same default weight and local preference values. Which statement is true about how BGP would select the best path?
A. If the command bgp always-compare-med has been given, then the router will prefer the route with the highest MED.
B. The router will prefer the shortest autonomous system path.
C. The router will prefer the route with the lower MED.
D. To influence one route to be preferred, its default local preference value will be changed via the use of the command bgp default local-preference 50.
Answer: B
Explanation:
In the Route selection decision process, if the weight, local preference & route originated are the
same then the shortest AS path will be chosen.
The full Route selection decision process is listed below:
1. Prefer highest weight (local to router)2. Prefer highest local preference (global within AS)3. Prefer route originated by the local router (next hop = 0.0.0.0)4. Prefer shortest AS path5. Prefer lowest origin code (IGP < EGP )6. Prefer lowest MED (exchanged between autonomous systems)7. Prefer EBGP path over IBGP path8. Prefer the path through the closest IGP neighbor (IGP cost)9. Prefer oldest route for EBGP paths10. Prefer the path with the lowest neighbor BGP router ID11. Prefer the path with the lowest neighbor IP address
Reference: http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a0080094431.shtml
NEW QUESTION: 2
Refer to the exhibit.
Which IP packets will be accepted from EBGP neighbor 10.1.1.1?
A. IP packets with a TTL count in the header that is equal to or greater than 253
B. IP packets with a TTL count in the header that is equal to or greater than 2
C. IP packets with a TTL count in the header that is equal to 2
D. IP packets with a TTL count in the header that is equal to 253
Answer: A
Explanation:
neighbor ip-addressttl- Configures the maximum number of hops that separate
security hops hop- two peers.
count * The hop-countargument is set to number of hops
ExamplE. that separate the local and remote peer. If the expected
Router(config-router)# TTL value in the IP packet header is 254, then the number
neighbor 10.1.1.1 ttl- 1 should be configured for the hop-countargument. The
security hops 2 range of values is a number from 1 to 254.
* When this feature is enabled, BGP will accept
incoming IP packets with a TTL value that is equal to or
greater than the expected TTL value. Packets that are not
accepted are silently discarded.
* The example configuration sets the expected
incoming TTL value to at least 253, which is 255 minus
the TTL value of 2, and this is the minimum TTL value
expected from the BGP peer. The local router will accept
the peering session from the 10.1.1.1 neighbor only if it
is 1 or 2 hops away.
Reference: http://www.cisco.com/c/en/us/td/docs/ios/12_2s/feature/guide/fs_btsh.html
NEW QUESTION: 3
You are given a project with a single virtual private cloud (VPC) and a single subnetwork in the us-central1 region. There is a Compute Engine instance hosting an application in this subnetwork. You need to deploy a new instance in the same project in the europe-west1 region. This new instance needs access to the application. You want to follow Google-recommended practices. What should you do?
A. 1. Create a subnetwork in the same VPC, in europe-west1.2. Create the new instance in the new subnetwork and use the first instance's private address as the endpoint.
B. 1. Create a VPC and a subnetwork in europe-west1.2. Expose the application with an internal load balancer.3. Create the new instance in the new subnetwork and use the load balancer's address as the endpoint.
C. 1. Create a VPC and a subnetwork in europe-west1.2. Peer the 2 VPCs.3. Create the new instance in the new subnetwork and use the first instance's private address as the endpoint.
D. 1. Create a subnetwork in the same VPC, in europe-west1.2. Use Cloud VPN to connect the two subnetworks.3. Create the new instance in the new subnetwork and use the first instance's private address as the endpoint.
Answer: A