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NEW QUESTION: 1
What is the PRIMARY goal of incident handling?
A. Improve the company's disaster recovery plan
B. Contain and repair any damage caused by an event.
C. Successfully retrieve all evidence that can be used to prosecute
D. Improve the company's ability to be prepared for threats and disasters
Answer: B
Explanation:
This is the PRIMARY goal of an incident handling process.
The other answers are incorrect because :
Successfully retrieve all evidence that can be used to prosecute is more often used in
identifying weaknesses than in prosecuting.
Improve the company's ability to be prepared for threats and disasters is more appropriate
for a disaster recovery plan.
Improve the company's disaster recovery plan is also more appropriate for disaster
recovery plan.
Reference : Shon Harris AIO v3 , Chapter - 10 : Law, Investigation, and Ethics , Page :
727-728

NEW QUESTION: 2
Azure Artifactsを使用して、作成、テスト、検証、および展開したパッケージを共有する予定です。
単一のフィードを使用して各パッケージの複数のビルドをリリースする必要があります。解決策は開発中のパッケージのリリースを制限する必要があります。
あなたは何を使うべきですか?
A. グローバルシンボル
B. 上流の情報源
C. ビュー
D. ローカルシンボル
Answer: B
Explanation:
説明
アップストリームソースを使用すると、単一のフィードで製品のすべての依存関係を管理できます。特定の商品のすべてのパッケージをその商品のフィードに公開し、その商品の依存関係を同じフィード内のリモートフィードから上流のソースを介して管理することをお勧めします。この設定にはいくつかの利点があります。
*単純さ:あなたのNuGet.config、.npmrc、またはsettings.xmlはちょうど1つのフィード(あなたのフィード)を含みます。
*確定性:あなたのフィードは順番にパッケージリクエストを解決するので、同じコミットまたはチェンジセットで同じコードベースを再構築することは同じパッケージのセットを使用します
*由来:あなたのフィードは上流のソースを通して保存されたパッケージの由来を知っているので、あなたがあなたのフィードに公開されたカスタムまたは悪意のあるコピーではなく、オリジナルのパッケージを使っていることを確認できます
*心の平安:上流のソースを通して使われるパッケージは最初の使用でフィードに保存されることが保証されています。アップストリームソースが無効化または削除された場合、またはリモートフィードが停止したか、依存しているパッケージを削除した場合は、引き続き開発と構築を行うことができます。成果物/概念/アップストリーム・ソース?view = vsts

NEW QUESTION: 3
Refer to the exhibit.

A new subnet with 60 hosts has been added to the network. Which subnet address should this network use to provide enough usable addresses while wasting the fewest addresses?
A. 192.168.1.64/27
B. 192.168.1.56/26
C. 192.168.1.64/26
D. 192.168.1.56/27
Answer: C
Explanation:
A subnet with 60 host is 2*2*2*2*2*2 = 64 -2 == 62
6 bits needed for hosts part. Therefore subnet bits are 2 bits (8-6) in fourth octet.
8 bits+ 8bits+ 8bits + 2bits = /26
/26 bits subnet is 24bits + 11000000 = 24bits + 192
2 56 - 192 = 64
0 -63
6 4 - 127