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NEW QUESTION: 1
You issue the following command to drop the PRODUCTS table: (Choose all that apply.) SQL > DROP TABLE products; Which three statements are true about the implication of this command?
A. All indexes on the table remain but they are invalidated.
B. All data in the table is deleted but the table structure remains.
C. All data along with the table structure is deleted.
D. All views and synonyms on the table remain but they are invalidated.
E. A pending transaction in the session is committed.
Answer: C,D,E

NEW QUESTION: 2
회사에서 AWS KMS 서비스를 사용하여 키 세트를 생성했습니다. 각 키가 특정 서비스에만 사용되는지 확인해야 합니다. 예를 들어, S3 서비스에만 사용되는 하나의 키를 원합니다. 이것이 어떻게 달성 될 수 있습니까?
선택 해주세요:
A. 키 정책에서 kms : ViaService 조건 사용
B. S3 서비스에서만 키에 액세스 할 수 있도록 허용하는 버킷 정책을 생성합니다.
C. S3 서비스에서만 키에 액세스 할 수 있도록 허용하는 IAM 정책을 생성합니다.
D. IAM 사용자를 정의하고 키를 할당 한 다음 필요한 서비스에 권한을 할당합니다.
Answer: A
Explanation:
Option A and B are invalid because mapping keys to services cannot be done via either the IAM or bucket policy Option D is invalid because keys for IAM users cannot be assigned to services This is mentioned in the AWS Documentation The kms:ViaService condition key limits use of a customer-managed CMK to requests from particular AWS services. (AWS managed CMKs in your account, such as aws/s3, are always restricted to the AWS service that created them.) For example, you can use kms:V1aService to allow a user to use a customer managed CMK only for requests that Amazon S3 makes on their behalf. Or you can use it to deny the user permission to a CMK when a request on their behalf comes from AWS Lambda.
For more information on key policy's for KMS please visit the following URL:
https://docs.aws.amazon.com/kms/latest/developereuide/policy-conditions.html The correct answer is: Use the kms:ViaServtce condition in the Key policy Submit your Feedback/Queries to our Experts

NEW QUESTION: 3
You work as a professional Ethical Hacker. You are assigned a project to test the security of www.we-are-secure.com. You are working on the Windows Server 2003 operating system. You suspect that your friend has installed the keyghost keylogger onto your computer. Which of the following countermeasures would you employ in such a situation?
A. Use on-screen keyboards and speech-to-text conversion software which can also be useful against keyloggers, as there are no typing or mouse movements involved.
B. Use commercially available anti-keyloggers such as PrivacyKeyboard.
C. Monitor the programs running on the server to see whether any new process is running on the server or not.
D. Remove the SNMP agent or disable the SNMP service.
Answer: A,B,C
Explanation:
It is very hard to detect a keylogger's activity. Hence, a Network Administrator should take the following steps as countermeasures against software keyloggers: Actively monitor the programs running on the server. Monitor the network whenever an application attempts to make a network connection. Use commercially available anti-keyloggers, such as PrivacyKeyboard. Update one's antivirus regularly. Use on-screen keyboards and speech-to-text conversion software which can also be useful against keyloggers, as there are no typing or mouse movements involved.
Answer C is incorrect. An SNMP service is not used for keystroke logging. Hence, removing an SNMP agent may be a valid option if, and only if, the server is vulnerable to SNMP enumeration.

NEW QUESTION: 4
모바일 애플리케이션을 설계하는 회사에서 일하고 있습니다. 플레이어 레코드가 다른 게임에 할당 된 서버를 유지 관리합니다. 추적 시스템은 새롭고 개발 중입니다.
이 응용 프로그램은 Entity Framework를 사용하여 Azure 데이터베이스에 연결합니다. 데이터베이스에는 플레이어 테이블과 게임 테이블이 있습니다.
플레이어를 추가 할 때 코드는 새로운 플레이어 레코드를 삽입하고 기존 게임 레코드와 새 플레이어 레코드 사이의 관계를 추가해야 합니다.
응용 프로그램은 올바른 gameId 및 playerId를 사용하여 CreatePlayerWithGame을 호출하여 프로세스를 시작합니다.
(라인 번호는 참고 용으로 만 포함됩니다.)

다음 명령문 각각에 대해 명령문이 참이면 예를 선택하십시오. 그렇지 않으면 아니오를 선택하십시오.
참고 : 각각의 올바른 선택은 한 점으로 가치가 있습니다.

Answer:
Explanation:

Explanation:
Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
.HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Post)
.WithMany(p => p.PostTags)
.HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Tag)
.WithMany(t => t.PostTags)
.HasForeignKey(pt => pt.TagId);
}
}