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NEW QUESTION: 1
Which three are true about upgrading Oracle Grid Infrastructure? (Choose three.)
A. Only the grid user can perform the upgrade.
B. The upgrade process will automatically install all mandatory patches for the current version of Oracle Grid Infrastructure.
C. Existing Oracle Database instances must be shut down before starting the upgrade.
D. An existing Oracle base can be used.
E. A direct upgrade can be performed only from the immediately preceding Oracle Grid Infrastructure version.
F. The newer version is installed in a separate Oracle Grid Infrastructure home on the same server as the existing version.
Answer: A,D,F
NEW QUESTION: 2
The nurse has been aggressively treating a 23 year old female who was admitted for Diabetic
Ketoacidosis 7 hours ago. The nurse has been closely monitoring an insulin drip and monitoring blood
glucose levels every hour. When is it appropriate to begin administration of subcutaneous insulin?
A. When the blood glucose level is between 50 and 100 mg/dL.
B. When the blood glucose level is between 100 - 200 mg/dL.
C. When the blood glucose level is between 150- 250 mg/dL.
D. When the blood glucose reaches 80 mg/dL.
Answer: B
Explanation:
It is appropriate to begin administration of subcutaneous insulin in a patient being treated for
Diabetic Ketoacidosis when the blood glucose level reaches between 100-200 mg/dL. When the blood
glucose reaches the desired level, begin subcutaneous insulin for approximately 2 hours before stopping
the intravenous insulin infusion.
NEW QUESTION: 3
On fixing date, the settlement payment of an NDF reflects the differential between the agreed forward rate and:
A. the days' average rate
B. the average rate over the NDF period
C. the daily high
D. the fixing spot rate
Answer: D
NEW QUESTION: 4
Which two IPv6 address pairs can be assigned on a point-to-point link with a /125 mask? (Choose two.)
A. 2001:DB8::9 and 2001:DB8::10
B. 2001:DB8::10 and 2001:DB8::17
C. 2001:DB8::1 and 2001:DB8::2
D. 2001:DB8::1 and 2001:DB8::18
Answer: B,C
Explanation:
2001:DB8::x/125 = 2001:0DB8:0000:0000:0000:0000:0000:00xx
1- The 0's disapear because the 3 zero ommiting rules: Leading zeros can be omitted Groups of four zeros can be abbreviated to a zero Multiple contiguous groups (2-byte groups) can be abbreviated to double colon (::) but only once. 2- IPv6 is made by 128bits, therefore 128-125 = 3 This means that the last 3 bits represent the hosts, just like in IPv4 3- IPv6 is represented in Hex numbers: Ex: 2001 = 00100001 4- Then you can determine the answer just like in IPv4 (or at least in a very similar way) 2001:DB8::1 and 2001:DB8::2 belong to the /125 mask because of the 3 last bits 2001:DB8::9 and 2001:DB8::10 are obviously not in the same /125 subnet (remember 10 in hex is much different thatn 10 in decimal) 2001:DB8::10 and 2001:DB8::17 fall into the /125 subnet 2001:DB8::1 and 2001:DB8::18 it goes beyond the /125 subnet 5- In case you didn't understand why: 2001:DB8::1 - 2001:DB8::9 = First Subnet's Host 2001:DB8::10 - 2001:DB8::18 = Second Subnet's Hosts