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NEW QUESTION: 1
Which three statements are functions that are performed by IKE phase 1? (Choose three.)
A. It protects the IKE exchange by negotiating a matching IKE SA policy.
B. It establishes IPsec security associations.
C. It builds a secure tunnel to negotiate IKE phase 1 parameters.
D. It negotiates IPsec SA parameters.
E. It protects the identities of IPsec peers.
F. It authenticates the identities of the IPsec peers.
Answer: A,E,F
Explanation:
The basic purpose of IKE phase 1 is to authenticate the IPSec peers and to set up a secure channel between the peers to enable IKE exchanges. IKE phase 1 performs the following functions:
Authenticates and protects the identities of the IPSec peers
Negotiates a matching IKE SA policy between peers to protect the IKE exchange
Performs an authenticated Diffie-Hellman exchange with the end result of having matching shared secret keys
Sets up a secure tunnel to negotiate IKE phase 2 parameters
Reference: http://www.ciscopress.com/articles/article.asp?p=25474&seqNum=7

NEW QUESTION: 2
Which of the following statements are true about Mash-Up Approach?
There are 2 correct answers to this question. Choose:
A. BW Data authorizations set-up honored
B. Real-time data access from SAP BI
C. Continuous maintenance needed
D. High effort and investment
Answer: A,B

NEW QUESTION: 3
In the P FAT AP's SSID "H3C" upper rate limit enable wireless users, the configuration shown in FIG.
Based on the above configuration, which of the following statements are correct? (Multiple choice)
A. If the number of current access users of this FAT AP is 10, the bandwidth per user cannot exceed 20000/10=2000Kbps.
B. The wireless user speed limit function of FAT AP is divided into static speed limit and dynamic speed limit. The above configuration achieves dynamic speed limit.
C. If the number of currently connected users of this FAT AP is 10, the maximum bandwidth per user cannot exceed 2000Kbps.
D. If the number of current access users of this FAT AP is 10, and 5 of them have no traffic, the bandwidth per user cannot exceed 20000/5=4000Kbps.
Answer: A,B,C,D