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NEW QUESTION: 1
Which two locations are the best locations that an end user can use to determine if an IP phone is working
in SRST mode? (Choose two.)
A. Cisco Unified Communications Manager Administration
B. physical IP phone settings
C. Cisco Unified SRST Router
D. Cisco Unified MGCP Fallback Router
E. IP phone display
Answer: B,E
Explanation:
Explanation/Reference:
Explanation:
IP Phone display and Physical phone IP settings are two locations were an end user can determine if an IP
phone is working in SRST mode.
NEW QUESTION: 2
Which tool can automatically install Oracle Cloud Infrastructure CLI?
A. APT
B. PIP
C. Python
D. RPM
Answer: B
Explanation:
Explanation
References:
https://docs.cloud.oracle.com/iaas/Content/API/SDKDocs/climanualinst.htm
NEW QUESTION: 3
You need to recommend changes to the ERP application to resolve the search issue. The solution must minimize the impact on other queries generated from the ERP application.
What should you recommend changing?
A. The collation of the ProductName column
B. The index on the ProductName column
C. The data type of the ProductName column
D. The collation of the Products table
Answer: A
Explanation:
Explanation/Reference:
Reference:
http://technet.microsoft.com/en-us/library/aa214408(v=sql.80).aspx
NEW QUESTION: 4
あなたはモバイルアプリケーションを設計する会社で働いています。彼らは、プレーヤーの記録が異なるゲームに割り当てられるサーバーを維持しています。追跡システムは新しく、開発中です。
アプリケーションは、EntityFrameworkを使用してAzureデータベースに接続します。データベースには、PlayerテーブルとGameテーブルがあります。
プレーヤーを追加するとき、コードは新しいプレーヤーレコードを挿入し、既存のゲームレコードと新しいプレーヤーレコードの間に関係を追加する必要があります。
アプリケーションは、正しいgameIdとplayerIdを指定してCreatePlayerWithGameを呼び出し、プロセスを開始します。 （行番号は参照用にのみ含まれています。）
次の各ステートメントについて、ステートメントがtrueの場合は、[はい]を選択します。それ以外の場合は、[いいえ]を選択します。
注：正しい選択はそれぞれ1ポイントの価値があります。
Answer:
Explanation:
Explanation:
Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
.HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Post)
.WithMany(p => p.PostTags)
.HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
.HasOne(pt => pt.Tag)
.WithMany(t => t.PostTags)
.HasForeignKey(pt => pt.TagId);
}
}