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NEW QUESTION: 1
Ein Designunternehmen verfügt in mehreren unabhängigen Systemen über mehrere Namens- und Adressdateien für seine Kunden.
Welches der folgenden Steuerelemente ist das BESTE Steuerelement, um sicherzustellen, dass der Name und die Adresse des Kunden in allen Dateien übereinstimmen?
A. Verwendung autorisierter Änderungsformulare für Stammdateien
B. Regelmäßige Überprüfung jeder Masterdatei durch das Management
C. Abgleich von Datensätzen und Überprüfung von Ausnahmeberichten
D. Verwendung von Hash-Summen in Kundendatensätzen
Answer: A
NEW QUESTION: 2
When a retained asset account is established in the place of a cash settlement, an interest bearing account is created by the insurer for the beneficiary. The beneficiary receives a checkbook with which to draw upon funds in the new account. The account holder can make:
A. Partial or total withdrawal of the account balance as needed and has total control over the account
B. Total withdrawal of the account balance as needed and has total control over the account
C. 25% withdrawal of the account balance as needed and has total control over the account.
D. Partial withdrawal of the account balance as needed and has total control over the account
Answer: A
NEW QUESTION: 3
class MyTask extends RecursiveTask<Integer> {
final int low;
final int high;
static final int THRESHOLD = /* . . . */
MyTask (int low, int high) { this.low = low; this.high = high; }
Integer computeDirectly()/* . . . */
protected void compute() {
if (high - low <= THRESHOLD)
return computeDirectly();
int mid = (low + high) / 2;
invokeAll(new MyTask(low, mid), new MyTask(mid, high));
A. Option D
B. Option E
C. Option A
D. Option B
E. Option C
F. Option F
Answer: A,C
Explanation:
D: the compute() method must return a result.
A: These results must be combined (in the line invokeAll(new MyTask(low, mid), new MyTask(mid, high));)
Note 1: A RecursiveTask is a recursive result-bearing ForkJoinTask.
Note 2: The invokeAll(ForkJoinTask<?>... tasks) forks the given tasks, returning when isDone holds for each task or an (unchecked) exception is encountered, in which case the exception is rethrown.
Note 3: Using the fork/join framework is simple. The first step is to write some code that performs a segment of the work. Your code should look similar to this:
if (my portion of the work is small enough) do the work directly else split my work into two pieces invoke the two pieces and wait for the results Wrap this code as a ForkJoinTask subclass, typically as one of its more specialized types RecursiveTask(which can return a result) or RecursiveAction.