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NEW QUESTION: 1
A big value for F will result in:
A. an acceptance of H0.
B. a rejection of H0.
C. the test statistic falling in the acceptance region.
Answer: B
Explanation:
A big value for F will result in a rejection of H0.
NEW QUESTION: 2
NO: 211
Reporting from a Star schema is simpler than reporting from a normalized online transactional processing (OLTP) schema.
What are the reasons for wanting simpler reporting? (Choose all that apply.)
A. A Star schema typically has fewer tables than a normalized schema. Therefore, queries are simpler because they require fewer joins.
B. A Star schema is standardized and narrative; you can find the information you need for a report quickly.
C. There are specific Transact-SQL expressions that deal with Star schemas.
D. A Star schema has better support for numeric data types than a normalized relational schema; therefore, it is easier to create aggregates.
Answer: A,B
Explanation:
Explanation
References:
http://www.vertabelo.com/blog/technical-articles/data-warehouse-modeling-star-schema-vs-snowflake-schema
NEW QUESTION: 3
At which stage of the service lifecycle should the processes necessary to operate a new service be defined?
A. Service design: Design the processes
B. Service operation: IT operations management
C. Service strategy: Develop the offerings
D. Service transition: Plan and prepare for deployment
Answer: A
NEW QUESTION: 4
Which description of clustered Data ONTAP 8.2 Infinite Volume (InfiniVol) is true?
A. Infinite Volume Vservers and FlexVol Vservers cannot co-exist
B. Infinite Volume Vservers can share aggregates
C. Infinite Volume Vservers use Traditional volumes
D. Infinite Volume Vservers and FlexVol Vservers can co-exist in the same cluster
Answer: D
Explanation:
https://library.netapp.com/ecmdocs/ECMP1196798/html/GUID-E643017F-041B-4ECC-BEA1E4D80E26A47E.html