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NEW QUESTION: 1
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten für diese Frage.
Sie haben eine Datenbank für ein Bankensystem. Die Datenbank enthält zwei Tabellen mit den Namen tblDepositAcct und tblLoanAcct, in denen Einlagen- und Darlehenskonten gespeichert sind. Beide Tabellen enthalten folgende Spalten:
Sie müssen die Gesamtzahl der Kunden ermitteln, die entweder Einlagenkonten oder Darlehenskonten haben, jedoch nicht beide Kontotypen.
Welche Transact-SQL-Anweisung sollten Sie ausführen?
A. SELECT COUNT (*) FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
B. SELECT COUNT (DISTINCT L.CustNo) VON tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
C. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
D. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT (*) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT (DISTINCT D.CustNo) FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
G. SELECT COUNT (DISTINCT COALESCE (D.CustNo, L.CustNo)) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWhere
H. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: G
Explanation:
Erläuterung
SQL Server stellt den vollständigen Outer-Join-Operator FULL OUTER JOIN bereit, der alle Zeilen aus beiden Tabellen enthält, unabhängig davon, ob die andere Tabelle einen übereinstimmenden Wert hat oder nicht.
Betrachten Sie einen Join der Product-Tabelle und der SalesOrderDetail-Tabelle in ihren ProductID-Spalten. Die Ergebnisse zeigen nur die Produkte mit Kundenaufträgen. Der Operator ISO FULL OUTER JOIN gibt an, dass alle Zeilen aus beiden Tabellen in die Ergebnisse einbezogen werden sollen, unabhängig davon, ob die Tabellen übereinstimmende Daten enthalten.
Sie können eine WHERE-Klausel mit einem vollständigen Outer-Join einfügen, um nur die Zeilen zurückzugeben, bei denen keine übereinstimmenden Daten zwischen den Tabellen vorhanden sind. Die folgende Abfrage gibt nur die Produkte zurück, die keine übereinstimmenden Kundenaufträge haben, sowie die Kundenaufträge, die nicht mit einem Produkt übereinstimmen.
USE AdventureWorks2008R2;
GEHEN
- Das Schlüsselwort OUTER nach dem Schlüsselwort FULL ist optional.
SELECT p.Name, sod.SalesOrderID
AB Produktion.Produkt p
VOLLSTÄNDIGE AUSSENVERBINDUNG Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IST NULL
OR sod.ProductID IS NULL
ORDER BY p.Name;
Referenzen: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx
NEW QUESTION: 2
Consider a table my_table , with contents shown:
You execute:
SELECT a b, b a
FROM my_table
WHERE a < s
ORDER BY b;
What does this statement return?
A. Option B
B. Option D
C. 
D:
E:
D. Option C
E. Option E
F. an error message
B:
Answer: B
NEW QUESTION: 3
組織は最近、カスタムWebアプリケーションをクラウドに移行し、サブスクリプションの一部としてバックエンド環境のマネージドサービスを取得しています。この会社が現在使用しているサービスは次のうちどれですか？
A. IaaS
B. SaaS
C. CASB
D. PaaS
Answer: C
Explanation:
Security Broker (CASB) gives you both visibility into your entire cloud stack and the security automation tool your IT team needs.
NEW QUESTION: 4
A computer has not reported in for over an hour and is grayed out in the IBM Endpoint Manager (IEM) console. Which option in the IEM console forces the client to report back in assuming the operator has no remote access to the endpoint?
A. Restart the Client Service
B. Send Refresh
C. Send Client Reset
D. Clear Console Cache
Answer: C