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NEW QUESTION: 1
A hospital is running a project for one of their internal critical systems to manage billing patient data and record management along with consultation reports and input from physicians The project manager now needs to categorize the identified risks Drag each risk type on the left to its correct example on the right
Answer:
Explanation:
NEW QUESTION: 2
-- Exhibit -
user@RP> show pim join extensive Instance: PIM.master Family: INET R = Rendezvous Point Tree, S = Sparse, W = Wildcard
Group: 224.1.1.1 Source: * RP: 192.168.1.1 Flags: sparse,rptree,wildcard Upstream interface: Local Upstream neighbor: Local Upstream state: Local RP Downstream neighbors: Interface: so-0/0/0.0
10.0.1.2 State: Join Flags: SRW Timeout: 176
Group: 224.1.1.1
Source: 10.0.5.2
Flags: sparse,spt
Upstream interface: unknown (no nexthop)
Upstream neighbor: unknown
Upstream state: Local RP
Keepalive timeout: 106
Downstream neighbors:
Interface: so-0/0/0.0
10.0.1.2 State: Join Flags: S Timeout: 176
Instance: PIM.master Family: INET6 R = Rendezvous Point Tree, S = Sparse, W = Wildcard -- Exhibit -
Click the Exhibit button.
The CLI output shown in the exhibit was taken from the RP in a PIM-SM network.
Which statement explains the output shown in the exhibit?
A. The router does not have a unicast route to 10.0.5.2.
B. No tunnel PIC is installed on the RP router.
C. 192.168.1.1 is not a local IP address on the RP router.
D. Multicast traffic is arriving on the so-0/0/0.0 interface.
Answer: A
NEW QUESTION: 3
You are responsible for providing access to an Azure Data Lake Storage Gen2 account.
Your user account has contributor access to the storage account, and you have the application ID access key.
You plan to use PolyBase to load data into Azure SQL data warehouse.
You need to configure PolyBase to connect the data warehouse to the storage account.
Which three components should you create in sequence? To answer, move the appropriate components from the list of components to the answer are and arrange them in the correct order.
Answer:
Explanation:
Explanation:
Step 1: a database scoped credential
To access your Data Lake Storage account, you will need to create a Database Master Key to encrypt your credential secret used in the next step. You then create a database scoped credential.
Step 2: an external data source
Create the external data source. Use the CREATE EXTERNAL DATA SOURCE command to store the location of the data. Provide the credential created in the previous step.
Step 3: an external file format
Configure data format: To import the data from Data Lake Storage, you need to specify the External File Format. This object defines how the files are written in Data Lake Storage.
References:
https://docs.microsoft.com/en-us/azure/sql-data-warehouse/sql-data-warehouse-load-from-azure-data-lake-store
NEW QUESTION: 4
A. true . . \ . . \ . . \ annualreport.txt
B. false \quarter\ . . \qtrlreport.txt
C. false \sales\quarter\ . . \qtrlreport.txt
D. true \ . . \ . . \annualreport.txt
Answer: C
Explanation:
( richtig !! import java.nio.file.Path; import java.nio.file.Paths; ) original-Aufgabe war ( falsch >> import java.io.file.Path; import java.io.file.Paths; ) The relativize method that can be used to construct a relative path between two paths. relativize Path relativize(Path other) Constructs a relative path between this path and a given path. Parameters:other - the path to relativize against this path Returns:the resulting relative path, or an empty path if both paths are equal Note: Relativization is the inverse of resolution. This method attempts to construct a relative path that when resolvedagainst this path, yields a path that locates the same file as the given path. For18example, on UNIX, if this path is "/a/b" and the given path is "/a/b/c/d" then the resulting relative path would be"c/d". Where this path and the given path do not have a root component, then a relative path can beconstructed. A relative path cannot be constructed if only one of the paths have a root component. Where bothpaths have a root component then it is implementation dependent if a relative path can be constructed. If thispath and the given path are equal then an empty path is returned. For any two normalized paths p and q, where q does not have a root component,p.relativize(p.resolve(q)).equals(q) When symbolic links are supported, then whether the resulting path, when resolved against this path, yields apath that can be used to locate the same file as other is implementation dependent. For example, if this path is"/a/b" and the given path is "/a/x" then the resulting relative path may be "../x". If "b" is a symbolic link then isimplementation dependent if "a/b/../x" would locate the same file as "/a/x".