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NEW QUESTION: 1
Which of the following event detection techniques uses User and Entity Behavior Analytics (UEBA)?
A. Signature-based detection
B. Anomaly-based detection
C. Heuristic-based detection
D. Rule-based detection
Answer: B
NEW QUESTION: 2
A. Option B
B. Option C
C. Option A
D. Option D
Answer: C
NEW QUESTION: 3
Refer to the exhibit.
IP phone 1 has MAC address of 1111.1111.1111, and IP phone 2 has MAC address of 2222.2222.2222.
The first two incoming calls rang both phones and were answered by IP phone 2.
Which option describes what will happen to the third incoming call?
A. Neither phone rings and the call is forwarded to 2100.
B. Neither phone rings and the call is forwarded to 2200.
C. Both phones ring, but only IP phone 1 can answer the call.
D. Only IP phone 1 rings and can answer the call.
E. Both phones ring and either phone can answer the call.
Answer: D
Explanation:
Explanation/Reference:
Explanation:-As we can see busy-trigger-per-button set to 2 in voice register pool 1(IP Phone
1).So ipphone 1's channel is free for receiving incoming calls and right now IPPhone 2 is busy answering call.
NEW QUESTION: 4
Refer to the exhibit.
The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and
208.149.23.96?
A. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0
2 08.149.23.96[110/3] via 190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0
208.149.23.96[110/13] via 190.173.23.10, 00:00:16, Serial1/0
208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
C. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0
2 08.149.23.96[110/3] via 190.173.23.10, 00:00:16, Serial1/0
D. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0
2 08.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
Answer: D
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 /
Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets ->
The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps =
64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link ->
Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0.
In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.