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NEW QUESTION: 1
You have a new HPE BladeSystem C7000 enclosure to add to your existing HPE OneView appliance as a managed resource. What is the proper PowerShell Cmdlet to achieve this task?
A. Add-HPOVEnclosure -Hostname 192.168.1.100 -Username Administrator -Password MyP@ssw0rd
B. Add-HPOVServer -Hostname 192.121.8.406 -Username Administrator -Password MyP@ssw0rd
C. New-HPOVLogicalEnclosure -Name 192.121.8.406
D. Add-HPOVPowerDevice -Hostname 192.168.1.100 -Username admin -Password MyP@ssw0rd
Answer: C
NEW QUESTION: 2
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:
You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
B. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
C. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
D. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
E. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
Answer: A
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php
NEW QUESTION: 3
You have configured an Integration Procedure element with SEND/RESPONSE TRANSFORMATIONS as shown. Alternatively, how would you configure Additional Input to send exactly the same data? Assume that you check Send Only Additional Input.
A)
B)
C)
D)
A. OptionA
B. OptionD
C. OptionB
D. OptionC
Answer: B
NEW QUESTION: 4
Which code, inserted at line 10, generates the output "Hello World"?
#include <iostream> #include <string>
using namespace std;
string fun(string, string);
int main()
{
string s="Hello";
string *ps;
ps = &s;
//insert code here
return 0;
}
string fun(string s1, string s2)
{
return s1+s2;
}
A. cout << fun("Hello", " World");
B. cout << fun("Hello");
C. cout << fun(*ps);
D. cout << fun(" World");
Answer: A