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NEW QUESTION: 1
Which two options allow the creation and modification of APIs in IBM API Connect? (Select two.)
A. API Designer
B. Cloud Management Console
C. GatewayScript
D. API Manager
E. Developer Portal
Answer: A,C
NEW QUESTION: 2
What creates calendar entries on a users individual calendar? (Choose two.)
A. Approved resource plan.
B. Allocated resource plan.
C. Confirmed resource plan.
D. Planned resource plan.
Answer: C,D
NEW QUESTION: 3
Regarding the processing mode of MPLS for TTL, which description is correct?
A. Uniform simulation, when the IP packet passes through the MPLS network, the IP TTL of the ingress node is decremented by 1, and the MPLS TTL field is a fixed value.
B. The TTL of the MPLS label has the same meaning as the TTL in the IP header, which can prevent the MPLS network from generating a routing loop
C. In MPLS VPN, if you want to hide the structure of the MPLS backbone network, you can use the uniform mode for Ingress packets for private network packets.
D. In Pipe mode, when an IP packet passes through the MPLS network, the IP TTL is decremented by 1 to the MPLS TTL field on the ingress node.
Answer: B
NEW QUESTION: 4
A. SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks
B. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
G. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: E